Question:medium

The velocity of an electron in the second orbit of sodium atom (atomic number = 11) is \( v \). The velocity of an electron in its fifth orbit will be:

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The velocity of an electron in a Bohr orbit is inversely proportional to the square root of the principal quantum number \( n \).
Updated On: Apr 22, 2026
  • \( v \)
  • \( \frac{22}{5}v \)
  • \( \frac{5}{2}v \)
  • \( \frac{2}{5}v \)
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The Correct Option is D

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