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The vector sum of two forces $\vec{A}$ and $\vec{B}$ is perpendicular to their vector difference. Hence forces $\vec{A}$ and $\vec{B}$ are}
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Sum and Difference vectors are perpendicular only for equal magnitude vectors (diagonals of a rhombus).
MHT CET - 2025
MHT CET
Updated On:
Jun 19, 2026
perpendicular to each other.
parallel to each other.
unequal in magnitude.
equal in magnitude.
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The Correct Option is
D
Solution and Explanation
Step 1: Understanding the Question:
We use the dot product property for perpendicular vectors.
Step 2: Key Formula or Approach:
If \( \vec{X} \perp \vec{Y} \), then \( \vec{X} \cdot \vec{Y} = 0 \).
Step 3: Detailed Explanation:
Given \( (\vec{A} + \vec{B}) \perp (\vec{A} - \vec{B}) \).
\[ (\vec{A} + \vec{B}) \cdot (\vec{A} - \vec{B}) = 0 \]
\[ \vec{A} \cdot \vec{A} - \vec{A} \cdot \vec{B} + \vec{B} \cdot \vec{A} - \vec{B} \cdot \vec{B} = 0 \]
Since dot product is commutative (\( \vec{A} \cdot \vec{B} = \vec{B} \cdot \vec{A} \)):
\[ |\vec{A}|^2 - |\vec{B}|^2 = 0 \implies A^2 = B^2 \]
\[ A = B \]
Step 4: Final Answer:
The forces are equal in magnitude.
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