Question:medium

The variation of the stopping potential ($V_0$) with the frequency of incident radiation ($\nu$) is plotted. If $\nu_0$ is the threshold frequency, $h$ is Planck's constant, and $e$ is the electronic charge, then the slope of the graph with the frequency axis is:

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The slope of a stopping potential versus frequency graph is a universal constant ($\frac{h}{e}$). It remains exactly the same no matter what type of metal surface is chosen for the photoelectric experiment!
Updated On: May 16, 2026
  • $\frac{h\nu_0}{V_0}$
  • $\frac{V_0}{\nu_0}$
  • $\frac{\nu_0}{V_0}$
  • $\frac{h}{e}$
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The Correct Option is D

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