Question:medium

The value of \(\sin\theta+\cos(90^\circ+\theta)+\sin(180^\circ-\theta)+\sin(180^\circ+\theta)\) is

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Remember: \[ \sin(180^\circ-\theta)=\sin\theta, \quad \sin(180^\circ+\theta)=-\sin\theta. \]
Updated On: Jun 5, 2026
  • \(0\)
  • \(-1\)
  • \(1\)
  • \(\frac12\)
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Know the goal.
We must add four trigonometric terms that all involve the same angle $\theta$. The smart move is to change every term into a plain $\sin\theta$ using the standard angle rules, so they can cancel.

Step 2: Use the rule for $\cos(90^\circ+\theta)$.
Adding $90^\circ$ turns cosine into a negative sine. \[ \cos(90^\circ+\theta)=-\sin\theta \]

Step 3: Use the rule for $\sin(180^\circ-\theta)$.
In the second quadrant sine stays positive. \[ \sin(180^\circ-\theta)=\sin\theta \]

Step 4: Use the rule for $\sin(180^\circ+\theta)$.
In the third quadrant sine becomes negative. \[ \sin(180^\circ+\theta)=-\sin\theta \]

Step 5: Substitute everything in.
Replace each term in the original expression. \[ \sin\theta+(-\sin\theta)+\sin\theta+(-\sin\theta) \]

Step 6: Cancel and finish.
The first and second cancel, and the third and fourth cancel, leaving nothing. \[ =0 \] So the whole sum is $0$, which is option 1. \[ \boxed{0} \]
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