Question:easy

The value of $\sin 45^\circ$ is

Show Hint

At $45^\circ$, the sine and cosine values are identical because the opposite and adjacent sides of the triangle are equal. Therefore, $\sin 45^\circ = \cos 45^\circ = 1/\sqrt{2}$.
  • $\sqrt{2}$
  • $1$
  • $0$
  • $1/\sqrt{2}$
Show Solution

The Correct Option is D

Solution and Explanation

1. Geometric Derivation: Consider a right-angled triangle where the other two angles are $45^\circ$ each. In such a triangle, the two legs must be equal in length. Let the length of each leg be $x$.

2. Using Pythagoras Theorem: $$\text{Hypotenuse}^2 = \text{side}_1^2 + \text{side}_2^2$$ $$h^2 = x^2 + x^2 = 2x^2$$ $$h = \sqrt{2x^2} = x\sqrt{2}$$

3. Calculating Sine: By definition, $\sin \theta = \frac{\text{Opposite}}{\text{Hypotenuse}}$. For $\theta = 45^\circ$: $$\sin 45^\circ = \frac{x}{x\sqrt{2}}$$ $$\sin 45^\circ = \frac{1}{\sqrt{2}}$$ Numerically, this value is approximately $0.7071$.
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