Question:medium
The value of \( k \), if the circles \( 2x^2 + 2y^2 - 4x + 6y = 3 \) and \( x^2 + y^2 + kx + y = 0 \) cut orthogonally is:
The value of \( k \), if the circles \( 2x^2 + 2y^2 - 4x + 6y = 3 \) and \( x^2 + y^2 + kx + y = 0 \) cut orthogonally is:
Show Hint
For orthogonal circles, always convert equations to the form
\( x^2 + y^2 + 2gx + 2fy + c = 0 \), then use:
\[
2(g_1 g_2 + f_1 f_2) = c_1 + c_2
\]
Updated On: Apr 30, 2026
- \( 2 \)
- \( 3 \)
- \( 4 \)
- \( 5 \)
- \( 1 \)
Show Solution
The Correct Option is A
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