Question:medium

The value of \[ \int_{0}^{\infty}\frac{x^{2}(1-x^{2})}{(1+x)^{24}}\,dx \] is

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For integrals over \((0,\infty)\), \[ \boxed{x\rightarrow\frac1x} \] is a useful substitution. If the integrand changes sign under this transformation, then the integral is \[ \boxed{0.} \]
Updated On: Jul 14, 2026
  • \(0\)
  • \(8\)
  • \(24\)
  • \(1\)
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The Correct Option is A

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