Question:medium

The value of
\( \dfrac{3}{4} + \dfrac{15}{16} + \dfrac{63}{64} + \cdots \)
up to \( n \) terms is

Show Hint

Rewrite complex series as difference of simpler sums.
Updated On: Mar 20, 2026
  • \( n-\dfrac{4^n-1}{3} \)
  • \( n+\dfrac{4^n-1}{3} \)
  • \( n+\dfrac{4^n}{3}-\dfrac13 \)
  • n-(4ⁿ)/(3)+\dfrac13
Show Solution

The Correct Option is C

Solution and Explanation

Was this answer helpful?
0