Question:medium

The value of \[ \begin{vmatrix} 1 & a & b + c \\ 1 & b & c + a \\ 1 & c & a + b \end{vmatrix} \] is:

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Summing variables often reveals identical rows or columns in cyclic determinants.

Updated On: Apr 8, 2026

$a+b+c$
$(a-b)(b-c)(c-a)$
0
1

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The Correct Option is C

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The value of \[ \begin{vmatrix} 1 & a & b + c \\ 1 & b & c + a \\ 1 & c & a + b \end{vmatrix} \] is:

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The Correct Option is C

Solution and Explanation

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