Question:medium
The total energy of the particle executing simple harmonic motion of amplitude A is 100 J. At a distance of 0.707 A from the mean position, its kinetic energy is
The total energy of the particle executing simple harmonic motion of amplitude A is 100 J. At a distance of 0.707 A from the mean position, its kinetic energy is
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At \( x = A/\sqrt{2} \), Potential Energy equals Kinetic Energy. Each is exactly half of the Total Energy!
Updated On: May 6, 2026
- 25 J
- 50 J
- 100 J
- 12.5 J
- 70 J
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The Correct Option is B
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