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The three vertices of a triangle are \( (0,0) \), \( (3,1) \) and \( (1,3) \). If this triangle is inscribed in a circle, then the equation of the circle is
The three vertices of a triangle are \( (0,0) \), \( (3,1) \) and \( (1,3) \). If this triangle is inscribed in a circle, then the equation of the circle is
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For a circle passing through the origin, the constant term \(c\) in the general equation \(x^2+y^2+2gx+2fy+c=0\) is always zero. This instantly simplifies your system of equations, saving valuable time.
Updated On: Apr 21, 2026
- \( 2x^2 + 2y^2 - 2x - 6y = 0 \)
- \( x^2 + y^2 - 3x - y = 0 \)
- \( x^2 + y^2 - x - 3y = 0 \)
- \( 2x^2 + 2y^2 - 6x - 2y = 0 \)
- \( 2x^2 + 2y^2 - 5x - 5y = 0 \)
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The Correct Option is
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