The swimming pool is fitted with three pipes. The first two pipes operating simultaneously can fill the pool in half the time taken by the third pipe alone to fill the pool. What is the time taken by the three pipes individually to fill the pool?
Statement (1): The ratio between the time taken by the first and third pipes is 3 : 4.
Statement (2): The second pipe takes 12 hours more than the first pipe working alone and 8 hours more than third pipe working alone.
Set T3 = T and express T1, T2 in terms of T using each statement, then see whether the basic combined-rate equation ends up with T fully determined or not.
Call the individual filling times $T_1, T_2, T_3$ for pipes one, two and three. The problem tells us pipes one and two together are twice as fast as pipe three alone, which as a rate equation is $\frac{1}{T_1}+\frac{1}{T_2} = \frac{2}{T_3}$.
Testing statement (1) alone: it only fixes a ratio, $T_1 = \frac{3}{4}T_3$, so plug that in and solve for $T_2$ in terms of $T_3$: you'll get $T_2=\frac{3}{2}T_3$. Every quantity scales with $T_3$, but nothing anchors $T_3$ to an actual hour value — the pool could take 4 hours or 400 hours for pipe three and the ratio equation is still satisfied. No unique numeric answer, so not sufficient alone.
Testing statement (2) alone: here we get two linear relationships, $T_2 = T_1+12$ and $T_2=T_3+8$, both tying back to a single variable if we express everything through $T_3$: $T_1 = T_3-4$. Substitute both into the rate equation $\frac{1}{T_3-4}+\frac{1}{T_3+8}=\frac{2}{T_3}$ and this becomes one equation in the single unknown $T_3$, which simplifies to $4T_3=64$, so $T_3=16$, and consequently $T_1=12$, $T_2=24$. A unique, checkable numeric answer falls out, so statement (2) alone is sufficient.
Only statement (2) pins down actual numbers; statement (1) only pins down proportions. The answer is option (2).
What is the total mark in the examination?
Statements:
I. A student secures 36% but fails by 6 marks.
II. The pass mark is 60.