Idea / Expectation:
The Sun is at an extremely high temperature (core ≳ 107 K, surface ≈ 6000 K), so matter exists as a plasma, not as a solid or liquid.
At such temperatures, one might expect the Sun’s matter to behave like a gas, and hence its average mass density to be comparable to or only slightly higher than that of gases, rather than solids or liquids.
Let us check this expectation quantitatively.
Given:
Mass of the Sun, M = 2.0 × 1030 kg
Radius of the Sun, R = 7.0 × 108 m
Step 1: Calculate the volume of the Sun
Assuming the Sun to be spherical:
V = (4/3)πR3
V = (4/3)π (7.0 × 108)3
V ≈ 1.44 × 1027 m3
Step 2: Calculate the average mass density
Average density, ρ = M / V
ρ = (2.0 × 1030) / (1.44 × 1027)
ρ ≈ 1.39 × 103 kg m−3
Step 3: Compare with known densities
The Sun’s average density is of the same order as that of liquids (like water) and much higher than gases.
Conclusion:
Although the Sun is entirely in the plasma (gaseous) state due to its very high temperature, its enormous gravitational compression makes its average mass density comparable to that of liquids, not gases.
Thus, our initial expectation based only on temperature is not correct; gravity plays a dominant role in determining the Sun’s density.
Mass = \( (28 \pm 0.01) \, \text{g} \), Volume = \( (5 \pm 0.1) \, \text{cm}^3 \). What is the percentage error in density?