Question:medium

The sum \[ 1 + \frac{1+a}{2!} + \frac{1+a+a^2}{3!} + \cdots \] is equal to:

Show Hint

Break sums into known exponential series.
Updated On: Mar 23, 2026
  • \(e^a\)
  • \(\dfrac{e^a-e}{a-1}\)
  • \((a-1)e^a\)
  • (a+1)eᵃ
Show Solution

The Correct Option is B

Solution and Explanation

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