Question:medium

The standard free energy change $(\Delta G^{\circ})$ is related to equilibrium constant $(K)$ as

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$\Delta G^{\circ} = -RT \ln K$.
Updated On: May 2, 2026
  • $\Delta G^{\circ} = -2.303RT\ln K$
  • $\Delta G^{\circ} = 2.303RT\log K$
  • $\Delta G^{\circ} = RT\log K$
  • $\Delta G^{\circ} = -2.303RT\log K$
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The Correct Option is D

Solution and Explanation

Step 1: Conceptual Understanding:
$\Delta G^{\circ} = -RT \ln K$.
Step 2: Explanation in Detail:
$\Delta G^{\circ} = -RT \ln K = -2.303 RT \log K$.
Step 3: Therefore, Stating the Final Answer
$\Delta G^{\circ} = -2.303RT\log K$.
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