Think about dissolving table salt into a small glass of water at room temperature and stirring until no more will dissolve.
Since ordinary table salt matches the commonly quoted 36 gram figure in this amount of water, that is the correct answer.
Compare NaCl's solubility to other common salts to judge whether each option is a reasonable order of magnitude.
NaCl's moderate ionic solubility lines up with the 36 gram figure, making that the correct answer.
The freezing point depression constant (\( K_f \)) for water is \( 1.86 \, {°C·kg/mol} \). If 0.5 moles of a non-volatile solute is dissolved in 1 kg of water, calculate the freezing point depression.