Question:medium

The shielding constant of a 2p electron (calculated using Slater's rules) is

Show Hint

When applying Slater's rules, be careful not to count the electron for which you are calculating the shielding. For an electron in the (ns, np) group, all other electrons in that same group contribute 0.35.
Updated On: Feb 18, 2026
  • 3.30
  • 3.45
  • 4.55
  • 2.45
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Concept Overview:
Slater's rules estimate the effective nuclear charge (\(Z_{eff}\)) on an electron, calculated as the actual nuclear charge (Z) minus a shielding constant (\(\sigma\)). The screening effect of other electrons is represented by \(\sigma\), and the formula is \(Z_{eff} = Z - \sigma\). The problem asks for \(\sigma\) for a 2p electron. Without a specific atom, we'll test common ones.
Step 2: Key Formula:
Slater's rules for an ns or np electron:
1. Group the electronic configuration: (1s) (2s, 2p) (3s, 3p) (3d) etc.
2. Electrons in the same (ns, np) group contribute 0.35 to \(\sigma\).
3. Electrons in the (n-1) shell contribute 0.85.
4. Electrons in shells (n-2) or lower contribute 1.00.
Step 3: Calculation Example:
Calculate \(\sigma\) for a 2p electron in Oxygen (O, Z=8).
Oxygen's electronic configuration: 1s\(^2\) 2s\(^2\) 2p\(^4\).
Group according to Slater's rules: (1s\(^2\)) (2s\(^2\) 2p\(^4\)).
Calculate shielding for one 2p electron.
Electrons in the (2s, 2p) group: 2 (2s) + 3 (other 2p) = 5 electrons.
Contribution to \(\sigma\): \(5 \times 0.35 = 1.75\).
Electrons in the (n-1) shell (1s): 2 electrons.
Contribution to \(\sigma\): \(2 \times 0.85 = 1.70\).
Step 4: Answer:
Total shielding constant \(\sigma\):
\[ \sigma = 1.75 + 1.70 = 3.45 \]This matches option (2).
Was this answer helpful?
0