Question:medium

The second order derivative of which of the following functions is \( 20^x \)?

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When differentiating exponential functions with base \( a \), remember to multiply by \(\ln a\) each time. Conversely, when integrating, divide by \(\ln a\).
Updated On: Jun 12, 2026
  • \( \frac{20^x}{(\log_e 20)^2} \)
  • \( 20^x (\log_e 20)^2 \)
  • \( 20^x (\log_e 20) \)
  • \( \frac{20^x}{\log_e 20} \)
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The Correct Option is A

Solution and Explanation


Step 1: Understanding the Concept:

We need to find a function \( f(x) \) such that \( f''(x) = 20^x \). Recall that \( \frac{d}{dx}(a^x) = a^x \ln a \).

Step 2: Detailed Explanation:

Let \( f(x) = \frac{20^x}{(\ln 20)^2} \).
First derivative: \( f'(x) = \frac{d}{dx} \left[ \frac{20^x}{(\ln 20)^2} \right] = \frac{20^x \ln 20}{(\ln 20)^2} = \frac{20^x}{\ln 20} \).
Second derivative: \( f''(x) = \frac{d}{dx} \left[ \frac{20^x}{\ln 20} \right] = \frac{20^x \ln 20}{\ln 20} = 20^x \).

Step 3: Final Answer:

The function is \( \frac{20^x}{(\log_e 20)^2} \).
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