Question:medium

Given: \(y = a + b(x - 2022)\) is the least-squares straight-line trend.

Year (x)20202021202220232024
Profit (Rs. '000) (y)23452

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When fitting a linear trend, always check if you can simplify the time variable. If the number of years is odd, choosing the middle year as the origin (as done here with `X = x - 2022`) makes \(\sum X = 0\). This greatly simplifies the calculations for the least squares parameters 'a' and 'b'.
Updated On: Mar 27, 2026
  • 15
  • 5
  • 16
  • 2/3
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The Correct Option is C

Solution and Explanation

Step 1: Problem Definition: The objective is to determine the coefficients 'a' and 'b' for a linear trend line, \(y = a + bX\), fitted using the method of least squares. The time variable 'x' is transformed to a coded variable \(X = x - 2022\) to simplify computations.
Step 2: Applicable Formulas: The standard normal equations for a linear regression are given by:
\[ \sum y = na + b \sum X \]\[ \sum Xy = a \sum X + b \sum X^2 \]
Due to the coding \(X = x - 2022\), the sum of the coded time variable is zero (\(\sum X = 0\)). This simplifies the formulas to:
\[ a = \frac{\sum y}{n} \]
\[ b = \frac{\sum Xy}{\sum X^2} \]
Step 3: Calculation and Derivation: A table is constructed to compute the necessary sums. The coded variable \(X\) is derived by subtracting 2022 from each year. The table includes columns for Year (x), Profit (y), Coded Time (X), the product Xy, and the square of X (\(X^2\)).

Year (x)Profit (y)X = x - 2022Xy\(X^2\)
20202-2-44
20213-1-31
20224000
20235151
20242244
Sum\(\sum y = 16\)\(\sum X = 0\)\(\sum Xy = 2\)\(\sum X^2 = 10\)

The total number of data points, \(n\), is 5.

Applying the simplified formulas:
\[ a = \frac{16}{5} = 3.2 \]
\[ b = \frac{2}{10} = 0.2 \]
The problem requires the calculation of the ratio \(\frac{a}{b}\).
\[ \frac{a}{b} = \frac{3.2}{0.2} = \frac{32}{2} = 16 \]
Step 4: Conclusion: The ratio \(\frac{a}{b}\) is determined to be 16.
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