Question:medium

The roots of $(x-a)(x-a-1)+(x-a-1)(x-a-2)+(x-a)(x-a-2)=0, a \in R$ are always

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For any equation of the form $(x-a)(x-b) + (x-b)(x-c) + (x-c)(x-a) = 0$, the roots are always real.
Updated On: Apr 10, 2026
  • equal
  • imaginary
  • real and distinct
  • rational and equal
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The Correct Option is C

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