Question:medium
The resistance of a heating element is found to be \(120\Omega\) at room temperature which is \(20^\circ C\). If the temperature coefficient of the material of the resistor is \(1.6 \times 10^{-4}\,^\circ C^{-1}\) and the resistance is found to be \(160\Omega\), the temperature of the element is:
The resistance of a heating element is found to be \(120\Omega\) at room temperature which is \(20^\circ C\). If the temperature coefficient of the material of the resistor is \(1.6 \times 10^{-4}\,^\circ C^{-1}\) and the resistance is found to be \(160\Omega\), the temperature of the element is:
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Always use \(R = R_0[1 + \alpha (T - T_0)]\) for temperature problems and carefully handle small values of \(\alpha\).
Updated On: May 6, 2026
- \(1203^\circ C\)
- \(2083^\circ C\)
- \(2310^\circ C\)
- \(2013^\circ C\)
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The Correct Option is B
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