The relation between nm (nm = the number of permissible values of magnetic quantum number (m)) for a given value of azimuthal quantum number (l), is
l = 2nm + 1
nm = 2l2 + 1
nm = l + 2
\(l=\frac {n_m-1}{2}\)
To determine the relation between the number of permissible values for the magnetic quantum number \( n_m \) and a given azimuthal quantum number \( l \), let's delve into quantum mechanics.
In atomic physics, the magnetic quantum number \( m \) describes the orientation of the orbital’s angular momentum in space relative to a magnetic field. The azimuthal quantum number \( l \) defines the shape of the orbital, and it can take integer values from 0 to \( n-1 \), where \( n \) is the principal quantum number.
For a given azimuthal quantum number \( l \), the magnetic quantum number \( m \) can range from \(-l\) to \(+l\), including zero. This means:
\(m = -l, -l+1, \ldots, 0, \ldots, l-1, l\)
Therefore, the total number of permissible values for \( m \), which is \( n_m \), is calculated as:
\(n_m = 2l + 1\)
The correct relation is given by Option 4: \(l = \frac {n_m-1}{2}\). This accurately describes how one can calculate the azimuthal quantum number \( l \) if the number of magnetic quantum numbers \( n_m \) is known.
Remember, the relation \( n_m = 2l + 1 \) is fundamental for understanding orbitals and how they split in magnetic fields, key concepts in quantum chemistry.
Choose the correct option
| Molecule | Shape | ||
|---|---|---|---|
| A | \(BrF_5\) | i | T-shape |
| B | \(H_2O\) | ii | See-saw |
| C | \(ClF_3\) | iii | Bent |
| D | \(SF_4\) | iv | Square Pyramidal |