Question

The ratio of rate of diffusion of \(SO_2\) to \(CH_4\) is:

• A. \(1:1\)
• B. \(1:2\)
• C. \(2:1\)
• D. \(4:1\)

Hint:

According to Graham's law, \[ r \propto \frac{1}{\sqrt{M}} \] Hence, lighter gases diffuse faster than heavier gases.

Answer 1

The Correct Option is B

Step 1: Apply Graham's law: rate \(\propto 1/\sqrt{M}\).
M(SO\(_2\)) = 64 g/mol, M(CH\(_4\)) = 16 g/mol.

Step 2: Calculate the ratio.
\(rac{r_{SO_2}}{r_{CH_4}} = \sqrt{rac{16}{64}} = \sqrt{rac{1}{4}} = rac{1}{2}\). So the ratio is \(1:2\). \[ oxed{1:2} \]