Step 1: Let incomes of A and B be \(7x\) and \(6x\), and expenditures be \(5y\) and \(4y\). Since both save Rupees 600, \(7x-5y=600\) and \(6x-4y=600\).
Step 2: Eliminate \(x\) first. From the second equation, \(x=100+\dfrac{2y}{3}\). Substitute into the first: \(7\left(100+\dfrac{2y}{3}\right)-5y=600\), which simplifies to \(700+\dfrac{14y}{3}-5y=600\), so \(-\dfrac{y}{3}=-100\), giving \(y=300\).
Step 3: Put \(y=300\) back into \(6x-4(300)=600\), so \(6x=1800\) and \(x=300\).
Step 4: Incomes are \(7x=2100\) and \(6x=1800\), so their sum is \[ \boxed{3900} \]