Question:medium

The radius of the sphere $x^2 + y^2 + z^2 = 12x + 4y + 3z$ is

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For sphere $x^2+y^2+z^2+2ux+2vy+2wz+d=0$, radius is $\sqrt{u^2+v^2+w^2-d}$.
Updated On: Apr 10, 2026
  • $\frac{13}{2}$
  • 13
  • 26
  • 52
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The Correct Option is A

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