The radius of the circle passes through the foci of a conic \( \frac{x^2}{16} + \frac{y^2}{9} = 1 \) and has its centre at \( (0, 3) \), then the diameter of the circle is ---
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For an ellipse, the foci are located at a distance of \( c = \sqrt{a^2 - b^2} \) from the center along the major axis. The circle passing through the foci has its radius equal to the distance from the center to the foci.