Question:medium

The radius of second orbit of hydrogen atom is same as that of orbit (n) of an ion (x). n and x are respectively

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The radius of the nth Bohr orbit is proportional to \(n^2\) and inversely proportional to Z (\(r_n \propto n^2/Z\)). This relationship is key to solving comparison problems between different orbits and different hydrogen-like atoms.
Updated On: Mar 30, 2026
  • 4, Be\(^{2+}\)
  • 3, Li\(^{2+}\)
  • 4, Be\(^{3+}\)
  • 2, He\(^+\)
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The Correct Option is C

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