Question

The radius of first Bohr orbit of hydrogen atom is \(r_o\)\( \AA\). The wavelength (in \(\AA\)) of electron associated with sixth orbit of same atom is

• A. \(6\pi r_o\)
• B. \(3\pi r_o\)
• C. \(8\pi r_o\)
• D. \(12\pi r_o\) \bigskip

Hint:

For hydrogen atom, \[ r_n=n^2r_o \] and \[ 2\pi r_n=n\lambda_n \] Combining both, \[ \lambda_n=2\pi nr_o \] Thus for \(n=6\), \[ \lambda_6=12\pi r_o/2=6\pi r_o. \]

Answer 1

The Correct Option is A