Concept:
The nature of a lens is determined by its focal length.
According to the lens maker's formula,
\[
\frac{1}{f}
=
(\mu-1)
\left(
\frac{1}{R_1}
-
\frac{1}{R_2}
\right)
\]
For a plano-convex lens,
\[
R_1=20\,\text{cm},
\qquad
R_2=\infty
\]
and
\[
\mu=1.5
\]
Step 1:Calculate the focal length.
\[
\frac{1}{f}
=
(1.5-1)
\left(
\frac{1}{20}
-\frac{1}{\infty}
\right)
\]
\[
\frac{1}{f}
=
0.5\times\frac{1}{20}
\]
\[
\frac{1}{f}
=
\frac{1}{40}
\]
\[
f=40\,\text{cm}
\]
Step 2: Interpret the result.
Since
\[
f>0
\]
the lens is a converging (convex) lens.
Changing the side from which light enters does not change the nature of the lens.
Therefore, it behaves as a convex lens for objects placed on either side.
Step 3: State the answer.
\[
{
\begin{array}{c}
\text{A plano-convex lens acts as a convex lens}
\text{irrespective of the side on which the object lies.}
\end{array}
}
\]
Hence, the correct option is
\[
{(C)}
\]