To address this problem, we must calculate the combined power of four convex lenses and their total magnification relative to a single lens. The process is as follows:
Combined Power: When lenses are in direct contact, their total power \(P_{\text{total}}\) equals the sum of their individual powers. For four identical lenses, each with power \(p\), the total power is calculated as:
\[P_{\text{total}} = 4p\]
Total Magnification: A lens's magnification is determined by its focal length, which is inversely proportional to its power. The combined magnification \(M_{\text{total}}\) of four identical lenses arranged in series is the product of their individual magnifications. If one lens has a magnification of \(m\), then for four lenses:
\[M_{\text{total}} = m \times m \times m \times m = m^4\]
Summary: The combined power of the lenses is \(4p\), and their total magnification is \(m^4\). Consequently, the definitive answer is \(4p\) for power and \(m^4\) for magnification.