Step 1: Symmetry
The positive and negative half-cycles have equal areas, so they cancel exactly.
Step 2: Why the other options fail
10 A is the r.m.s. value. $7.072\ \text{A}$ is $\frac{10}{\sqrt{2}}$, which is not an average over a full cycle. $14.14\ \text{A}$ is the peak value.
Step 3: Result
Hence the average over a full cycle is zero.
Final Answer:
The average value of current over a cycle is zero.
\[ \boxed{\text{(A) }\text{Zero}} \]