Question:medium

The projection of vector \(\vec{A}=\hat{i}-2\hat{j}+\hat{k}\) on vector \(\vec{B}=4\hat{i}-4\hat{j}+7\hat{k}\) is:

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Be careful to distinguish between scalar projection (which is a number, as asked for here) and vector projection (which would be a vector: \( \frac{\vec{A} \cdot \vec{B}}{|\vec{B}|^2}\vec{B} \)). The formula divides by the magnitude \(|\vec{B}|\), not the magnitude squared.
Updated On: Feb 10, 2026
  • \( \frac{17}{9} \)
  • \( \frac{17}{7} \)
  • \( \frac{19}{7} \)
  • \( \frac{19}{9} \)
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The Correct Option is D

Solution and Explanation

Step 1: Remember the formula for the scalar projection of vector \(\vec{A}\) onto vector \(\vec{B}\), which is \(\text{proj}_{\vec{B}}\vec{A} = \frac{\vec{A} \cdot \vec{B}}{|\vec{B}|}\).
Step 2: Compute the dot product \(\vec{A} \cdot \vec{B}\). \(\vec{A} \cdot \vec{B} = (1)(4) + (-2)(-4) + (1)(7) = 4 + 8 + 7 = 19\).
Step 3: Determine the magnitude of vector \(\vec{B}\). \(|\vec{B}| = \sqrt{4^2 + (-4)^2 + 7^2} = \sqrt{16 + 16 + 49} = \sqrt{81} = 9\).
Step 4: Calculate the projection. \(\text{proj}_{\vec{B}}\vec{A} = \frac{19}{9}\).
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