Question:medium

The product of uncertainty in position \((\Delta x)\) and uncertainty in velocity \((\Delta v)\) has the unit of

Show Hint

Always double-check the units of physical quantities. The unit of velocity is m/s.
Updated On: May 10, 2026
  • \(m s^{-1}\)
  • \(m s^{-2}\)
  • \(m^2 s\)
  • \(m^{-2}s^{-1}\)
  • \(m s^{-2}s\)
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
This question deals with the units derived from the quantities in Heisenberg's Uncertainty Principle. The principle relates the uncertainty in a particle's position to the uncertainty in its momentum. We need to find the SI units for the product of uncertainty in position and uncertainty in velocity.
Step 2: Key Formula or Approach:
The product in question is \( (\Delta x) \times (\Delta v) \).
We need to determine the SI units for each term and then multiply them.

The SI unit for position (and thus uncertainty in position, \(\Delta x\)) is the meter (m).

The SI unit for velocity (and thus uncertainty in velocity, \(\Delta v\)) is meters per second (m/s or ms\(^{-1}\)).

Step 3: Detailed Explanation:
We multiply the units of the two quantities:
\[ \text{Unit of } (\Delta x \cdot \Delta v) = (\text{Unit of } \Delta x) \times (\text{Unit of } \Delta v) \] \[ = (\text{m}) \times (\text{m} \cdot \text{s}^{-1}) \] \[ = \text{m}^{1+1} \cdot \text{s}^{-1} \] \[ = \text{m}^2 \text{s}^{-1} \] The correct unit for the product of uncertainty in position and uncertainty in velocity is m\(^2\)s\(^{-1}\).
Upon reviewing the given options, none of them match the correctly derived unit of m\(^2\)s\(^{-1}\). There appears to be a typographical error in the question's options or the provided answer key. Heisenberg's Uncertainty Principle states \( \Delta x \cdot \Delta p \ge \frac{h}{4\pi} \), which implies \( \Delta x \cdot m\Delta v \ge \frac{h}{4\pi} \), and so the unit of \( \Delta x \cdot \Delta v \) is \( \frac{[h]}{[m]} = \frac{J \cdot s}{kg} = \frac{kg \cdot m^2 \cdot s^{-2} \cdot s}{kg} = m^2s^{-1} \).
However, as per the provided answer key, the correct option is (D). This indicates a significant error in the source material. We are noting this discrepancy for clarity.
Step 4: Final Answer:
Based on the provided answer key, the answer is option (D). However, based on fundamental principles of physics, the correct unit is m\(^2\)s\(^{-1}\), which is not listed.
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