The product of reaction between alcoholic silver nitrite with ethyl bromide is

Question

100 mL of 0.04 N HCl aqueous solution is mixed with 100 mL of 0.02 N NaOH solution. The pH of the resulting solution is:

Answer 1

To determine the product of the reaction between alcoholic silver nitrite and ethyl bromide, let's understand the chemical process involved.

**Explanation of Reaction:**

When ethyl bromide (C₂H₅Br) reacts with silver nitrite (AgNO₂) in alcoholic medium, the reaction proceeds via nucleophilic substitution.
Silver nitrite is ambidentate, meaning it can act as a nucleophile through either the nitrogen or oxygen atom. However, in this case, the nitrogen from silver nitrite attacks the ethyl group, leading to the formation of a nitro compound rather than a nitrite.

**Reaction Equation:**

\(\text{C}_2\text{H}_5\text{Br} + \text{AgNO}_2 \rightarrow \text{C}_2\text{H}_5\text{NO}_2 + \text{AgBr} \downarrow\)

Here, the bromine atom in ethyl bromide is replaced by the nitro group (NO₂), resulting in nitro ethane (C₂H₅NO₂).

**Conclusion:**

The product of this reaction is nitro ethane.
This results because the nitrogen acts as a nucleophile, leading to the formation of a nitro compound instead of an alkyl nitrite.

Thus, the correct answer is: nitro ethane.

Show Hint