Question:medium

The product formed in the following reaction is:

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HBr + Peroxide \(\Rightarrow\) Anti-Markovnikov addition through free radical mechanism.
Updated On: May 20, 2026
  • FigA
  • FigB
  • FigC
  • FigD
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The Correct Option is D

Solution and Explanation

Understanding the Concept: Addition of HBr in presence of peroxide follows anti-Markovnikov rule through free radical mechanism.
Step 1: Understanding peroxide effect.
In presence of benzoyl peroxide: \[ HBr \] adds via free radical pathway. Bromine radical attacks the double bond first.
Step 2: Stability of radical intermediate.
If bromine adds to terminal carbon: \[ \text{benzylic radical forms} \] Benzylic radicals are highly stable due to resonance. Therefore bromine attaches to the carbon farther from benzene ring.
Step 3: Final product formation.
Hydrogen attaches to benzylic carbon and bromine attaches to adjacent carbon. Thus product formed is: \[ HO-C_6H_4-CH_2-CH(Br)-CH_3 \]
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