The product formed in the following chemical reaction is:





To determine the product of the given chemical reaction, we need to understand the role of the reagents and the nature of the reaction.
The reaction involves the reduction of a compound by sodium borohydride (\(NaBH_4\)) in ethanol (\(C_2H_5OH\)). Sodium borohydride is a common reagent used for the reduction of ketones and aldehydes to alcohols.
Here, the reactant is a diketone compound with two carbonyl groups (\(C=O\)). Sodium borohydride selectively reduces carbonyl groups to alcohols.
Let us see how each carbonyl group is transformed:
Therefore, the expected reaction transforms both carbonyl groups into their respective alcohols.
The correct product, represented in the correct option above, shows both ketone groups reduced to alcohols.
Key takeaway: \(NaBH_4\) effectively reduces carbonyl compounds to alcohols, a crucial concept in understanding organic synthesis reactions.
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