Question:medium

The product and its colour when $\text{MnO}_2$ is fused with $\text{KOH}$ in presence of $\text{O}_2$:

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Keep the colors of manganese salts clear: Manganate ($\text{MnO}_4^{2-}$) is always dark green, while Permanganate ($\text{MnO}_4^-$) is always deep purple. Oxidative fusion of pyrolusite stops at the $+6$ green manganate state first!
Updated On: May 20, 2026
  • $\text{Mn}_2\text{O}_3$, Brown
  • $\text{KMnO}_4$, Purple
  • $\text{K}_2\text{MnO}_4$, Dark green
  • $\text{MnO}_2$, Black
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The Correct Option is C

Solution and Explanation

Understanding the Concept: This chemical transformation describes the initial step in the industrial synthesis of potassium permanganate ($\text{KKMnO}_4$) from pyrolusite ore ($\text{MnO}_2$). Fusing manganese dioxide with an alkali hydroxide in the presence of an oxidizing agent like air or $\text{KClO}_3$ oxidizes manganese from a $+4$ to a $+6$ oxidation state, forming a manganate salt.
Step 1: Analyze the chemical reaction equation.
The balanced chemical equation for the oxidative fusion process is: \[ 2\text{MnO}_2 + 4\text{KOH} + \text{O}_2 \xrightarrow{\Delta} 2\text{K}_2\text{MnO}_4 + 2\text{H}_2\text{O} \] The product formed is potassium manganate ($\text{K}_2\text{MnO}_4$).
Step 2: Identify the properties of the product compound.
The manganate ion ($\text{MnO}_4^{2-}$) contains a central manganese atom in a $+6$ oxidation state with a $\text{d}^1$ electron configuration. This unpaired electron causes the crystal lattice to absorb light in the visible spectrum, giving potassium manganate a characteristic dark green color. (Note: Further electrolytic oxidation or disproportionation under acidic conditions is required to convert this green manganate into purple permanganate, $\text{KMnO}_4$).
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