Question:medium

The probability distribution of a random variable \(X\) is given below. Then, the mean of \(X\) is 

\(X=x_i\)\(0\)\(1\)\(2\)
\(P(X=x_i)\)\(3k^2\)\(2k^2\)\(k^2+k\)

Show Hint

For a discrete random variable, \[ \boxed{E(X)=\sum x_iP(X=x_i).} \] Before finding the mean, always verify that \[ \boxed{\sum P(X=x_i)=1.} \]
Updated On: Jul 22, 2026
  • \(\dfrac79\)
  • \(\dfrac59\)
  • \(\dfrac{10}{9}\)
  • \(\dfrac{13}{9}\)
Show Solution

The Correct Option is C

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