The present ages of Rahul and his father are in the ratio 6 : 13. The ratio between the present ages of his father and his sister is 13 : 5. If the difference between the present ages of his mother and his sister is 28 years, what is the difference between the present ages of his father and his mother?
Statement (1): The ratio of the present ages of Rahul and his mother is 1 : 2.
Statement (2): The difference between the present ages of Rahul and his sister is 4 years.
Write Rahul, father, sister and mother's ages in terms of one variable x using the two given ratios, then check if each statement alone lets you solve for x.
Take Rahul's age as $r$, father's age as $f$, sister's age as $s$ and mother's age as $m$.
From the ratio $r:f = 6:13$, write $f = \frac{13r}{6}$.
From the ratio $f:s = 13:5$, since $f = \frac{13r}{6}$, we get $s = \frac{5r}{6}$ (the same 6 in the denominator, because $f$ is $13$ parts of the same unit that makes $s$ equal to $5$ parts).
Given $m - s = 28$, so $m = \frac{5r}{6} + 28$.
We want $f - m = \frac{13r}{6} - \frac{5r}{6} - 28 = \frac{8r}{6} - 28 = \frac{4r}{3} - 28$.
Statement (1) says $r:m = 1:2$, i.e. $m = 2r$. Setting this equal to the earlier expression for $m$: $2r = \frac{5r}{6} + 28 \Rightarrow 12r = 5r + 168 \Rightarrow 7r = 168 \Rightarrow r = 24$. Then $f - m = \frac{4(24)}{3} - 28 = 32 - 28 = 4$. A single, definite number, so statement (1) alone works.
Statement (2) says $r - s = 4$, i.e. $r - \frac{5r}{6} = 4 \Rightarrow \frac{r}{6} = 4 \Rightarrow r = 24$. Then $f - m = \frac{4(24)}{3} - 28 = 32-28 = 4$ again, a single definite number, so statement (2) alone works too.
Both routes land on the same answer of 4 years, confirming that either statement by itself is sufficient, option (4).
What is the total mark in the examination?
Statements:
I. A student secures 36% but fails by 6 marks.
II. The pass mark is 60.