Step 1: Analogy:
Linear motion has $P=Fv$. The rotational version is $P=\tau\omega$.
Step 2: Use torque:
$\tau=I\alpha$ so $P=I\alpha\omega$.
Step 3: Dimension check:
$P$ is $ML^2T^{-3}$, $I$ is $ML^2$, $\alpha$ is $T^{-2}$. So $P/(I\alpha)=T^{-3}/T^{-2}=T^{-1}$, which is angular velocity. Option (D).
Final Answer:
Only P / (I alpha) has the unit of angular velocity.
\[ \boxed{D} \]