Question:medium

The potentials at points A and B are \( V_A \) and \( V_B \) respectively for the charges \( +q \) and \( -q \) placed at distances ' x ' each from points A and B as shown in figure. The distance between points A and B is ' y '. The net potential (\( V_A - V_B \)) is proportional to

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- Potential is scalar → add algebraically - Carefully track distances for each charge
Updated On: May 4, 2026
  • \( \frac{2qy}{x(x+y)} \)
  • \( \frac{-2qy}{x(x+y)} \)
  • \( \frac{qy}{x(x+y)} \)
  • Zero
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The Correct Option is A

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