Question:medium

The potential energy of an electron in an orbit of hydrogen atom is -6.8 eV. The de Broglie wavelength of the electron in this orbit is ($r_0$ is Bohr radius)

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Remember the key relationships in the Bohr model: $E_n = -K_n = U_n/2$ and $E_n = -13.6/n^2$ eV. Also, Bohr's quantization condition can be combined with the de Broglie wavelength to give $2\pi r_n = n\lambda$, meaning the circumference of the orbit is an integer multiple of the de Broglie wavelength.

Updated On: Mar 30, 2026

$2\pi r_0$
$4\pi r_0$
$\pi r_0$
$3\pi r_0$

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The Correct Option is B

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