Question

The position of $-$Br in the compound shown (a vinyl bromide structure) can be classified as:

• A. Vinylic
• B. Allylic
• C. Benzylic
• D. Aryl

Hint:

Vinylic = $-$X on the double bond carbon. Allylic = $-$X on the carbon next to the double bond.

Answer 1

The Correct Option is A

Step 1: Types of halogen positions.
The classification depends on the hybridisation of the carbon bearing the halogen: vinylic (on $sp^2$ C of a $C=C$), allylic (adjacent to $C=C$), benzylic (adjacent to benzene ring), aryl (directly on benzene ring).
Step 2: Identifying the structure.
In a vinyl bromide, the $-$Br is bonded directly to a carbon that is part of a carbon-carbon double bond ($C=C$), so the carbon is $sp^2$ hybridised.
Step 3: Applying the classification.
A halogen directly on an $sp^2$ carbon of a $C=C$ bond is defined as a vinylic halide.
Step 4: Conclusion.
The position of $-$Br in the vinyl bromide structure is classified as vinylic.
\[ \boxed{\text{Vinylic}} \]