To determine the pH of a 0.01 M NaOH (aq) solution, we first need to understand the relationship between the pH and the concentration of a strong base like NaOH.
- NaOH is a strong base and dissociates completely in water. The dissociation can be represented as:
\text{NaOH} \rightarrow \text{Na}^+ + \text{OH}^- .
- The concentration of hydroxide ions [\text{OH}^-] is equal to the concentration of the NaOH solution. Therefore, in a 0.01 M NaOH solution,
[\text{OH}^-] = 0.01 \, \text{M}.
- The relationship between pH and pOH is given by the equation:
\text{pH} + \text{pOH} = 14.
- First, calculate the pOH of the solution:
\text{pOH} = - \log_{10} [\text{OH}^-] = - \log_{10}(0.01).
- Since 0.01 = 10^{-2},
\text{pOH} = 2.
- Using the relation \text{pH} + \text{pOH} = 14, we find:
\text{pH} = 14 - \text{pOH} = 14 - 2 = 12.
Thus, the pH of a 0.01 M NaOH solution is 12. This means that the solution is basic, as expected for a sodium hydroxide solution.
This confirms that the correct answer is 12, which matches the given correct option.