Question:medium

The per unit impedance of a circuit is 0.25. If the base kV and base MVA are halved, then the new value of p.u. impedance of the circuit will be :

Show Hint

Per-unit impedance: \[ Z_{pu}=\frac{Z_{actual}}{Z_{base}} \] with: \[ Z_{base}=\frac{(kV_{base})^2}{MVA_{base}} \]
Updated On: May 22, 2026
  • 0.4
  • 0.25
  • 0.5
  • 0.75
Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?
0


Questions Asked in CUET (PG) exam