Question:medium

The parametric equations of the circle $x^2 + y^2 - 4x - 6y - 12 = 0$ are:

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Center is $(-g, -f)$ and Radius is $\sqrt{g^2+f^2-c}$. For this circle, $g=-2, f=-3, c=-12$.
Updated On: May 16, 2026
  • $x = 2 + 5 \cos \theta, y = 3 + 5 \sin \theta$
  • $x = -2 + 5 \cos \theta, y = -3 + 5 \sin \theta$
  • $x = 2 + 25 \cos \theta, y = 3 + 25 \sin \theta$
  • $x = 5 + 2 \cos \theta, y = 5 + 3 \sin \theta$
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The Correct Option is A

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