Question:medium

The parametric equations of the circle $x^2 + y^2 - 4x - 6y - 12 = 0$ are:

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For $x^2+y^2+2gx+2fy+c=0$, the center is $(-g, -f)$ and $r = \sqrt{g^2+f^2-c}$.
Updated On: May 16, 2026
  • $x = 2 + 5 \cos \theta, y = 3 + 5 \sin \theta$
  • $x = -2 + 5 \cos \theta, y = -3 + 5 \sin \theta$
  • $x = 2 + 25 \cos \theta, y = 3 + 25 \sin \theta$
  • None of these
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The Correct Option is A

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