Step 1: Formula of ferrate ion.
The species is FeO₄²⁻, with each oxygen assigned an oxidation number of –2.
Step 2: Setting up the charge balance.
Let x be the oxidation state of Fe. Total oxygen contribution = 4×(–2) = –8.
Step 3: Equation for net charge.
x – 8 = –2.
Step 4: Solving for x.
x = +6.
Step 5: Conclusion.
Iron in the ferrate ion is in the +6 oxidation state.