Question:medium

The number of values of \(\theta\) lying in \([0, 2\pi]\) for which \(\sin 3\theta\) attains its maximum when \[ \left|\sin\theta \cdot \sin\left(\frac{\pi}{3} - \theta\right)\cdot \sin\left(\frac{\pi}{3} + \theta\right)\right| \le \frac{1}{8} \] is: 

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When dealing with trigonometric inequalities involving a product of sines, always look for the identity \(\sin 3\theta = 4 \sin \theta \sin(60^\circ - \theta) \sin(60^\circ + \theta)\) to simplify the expression.
Updated On: Jun 18, 2026
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The Correct Option is D

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