Question:medium

The number of terms in an arithmetic progression is 20. The sum of the four middle terms is (-22). What are the values of first term and common difference?
Statement 1: The sum of first four terms is 74
Statement 2: The difference between first term and common difference is 26

Show Hint

The four middle terms of a 20-term AP are the 9th to 12th terms; their sum gives one equation in a and d that either statement completes.
Updated On: Jul 21, 2026
  • If the data in statement (1) alone is sufficient to answer the question
  • If the data in statement (2) alone is sufficient to answer the question
  • If the data in both the statements together are needed to answer the question
  • If either statement (1) alone or statement (2) alone is sufficient to answer the question
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Translate the middle-terms condition into an equation.
With 20 terms, the four middle terms are the 9th through 12th terms: \(a+8d, a+9d, a+10d, a+11d\). Adding these: \(4a+38d=-22\). This equation is fixed by the question itself and always available.

Step 2: Try statement 2 first.
Statement 2 says \(a-d=26\). Rearranged, \(d=a-26\).
Substitute into \(4a+38d=-22\): \(4a+38(a-26)=-22 \Rightarrow 4a+38a-988=-22 \Rightarrow 42a=966 \Rightarrow a=23\).
Then \(d=23-26=-3\). Both values come out cleanly, so statement 2 alone is sufficient.

Step 3: Try statement 1 next.
Statement 1 gives the sum of the first four terms as 74: \(4a+6d=74\).
Pairing with \(4a+38d=-22\) and eliminating a by subtraction gives \(32d=-96\), so \(d=-3\), and then \(a=23\) from \(4a+6(-3)=74\).
The same pair of values appears again, so statement 1 alone is also sufficient.

Step 4: Conclude.
Both statements, taken one at a time along with the fixed middle-term sum, land on the same a = 23 and d = -3, confirming either statement alone is sufficient. \[ \boxed{\text{d}} \]
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